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Q.

A particle starting from rest moves along a circle of radius ‘R’ with a constant tangential acceleration . The angle made by its acceleration with velocity after the particle completes half revolution is

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a

450

b

tan−112π

c

π2

d

tan−12π

answer is C.

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Detailed Solution

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V=2as=2a×πR

ac=v2R=2aπϕ=tan−1acat=tan−12π

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