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Q.

A particle starting from rest, moves in a circle of radius ‘r’. It attains a velocity of $V_{0}$ m/s at the end of nth round. Its angular acceleration (in rad/ $s^{2}$ ) is

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a

$\frac{V_{0}^{2}}{4 π n r^{2}}$

b

$\frac{V_{0}}{2 π n r^{2}}$

c

$\frac{V_{0}^{2}}{4 π n r}$

d

$\frac{V_{0}}{n}$

answer is C.

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Detailed Solution

$ω_{0} = 0 ω = \frac{V}{r} θ = 2 π n$

$ω^{2} - ω_{0}^{2} = 2 α θ$

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