A particle starting from the origin (0 0) moves in a straight line in the (x, y) plane. Its coordinates at a later time are $(\sqrt{3}, 3)$ . The path of the particle makes with the x-axis an angle of

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45°

60°

30°

0°

answer is B.

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Detailed Solution

Displacement of the particle is $\sqrt{3} \hat{i} + 3 \hat{j}$
angle made by it with x - axis,
$\tan θ = \frac{3}{\sqrt{3}} = \sqrt{3}; θ = 60^{\circ}$

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