A particle starts moving from rest with uniform acceleration. It travels a distance x in the first 2 sec and a distance y in the next 2 sec. Then

In first 2 seconds,

$\text{s}=\text{ut}+\frac{1}{2}{\text{at}}^{\text{2}}$

${\text{s}}_1=0+\frac{1}{2}\text{a}{\left(2\right)}^2$

$x={\text{s}}_{\text{1}}=2\text{a}\to \left(1\right)$

In time of 4 seconds,

${\text{s}}_{\text{2}}=\left(0\right)\left(4\right)+\frac{1}{2}\text{a}{\left(4\right)}^2$

${\text{s}}_{\text{2}}=0+8\text{a}$

${\text{s}}_{\text{2}}=8\text{a}\to \left(2\right)$

${\text{s}}_{\text{2}}-{\text{s}}_{\text{1}}=8\text{a}-2\text{a}$

From (1) & (2)

$\text{y}=\text{6a}$

$=\text{3}\left(\text{2a}\right)$

$\text{y}=\text{3}x$