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Q.

A particle starts from rest, accelerates at 2 m/s2 for 10 s and then goes for constant speed for 30 s and then decelerates at 4 m/s2 till it stops. What is the distance travelled by it?

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a

800 m

b

700 m

c

850 m

d

750 m

answer is A.

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Detailed Solution

s=s1+s2+s3

= 12a1t12+a1t1t2+a1t122×a2

=12×2×(10)2+(2)(10)(30)+2×1022×4   =100+600+50   =750 m

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