Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5

Q.

A particle starts from rest, its acceleration - time graph is shown in figure. Find out velocity at  t=4 sec

Question Image

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!
An Intiative by Sri Chaitanya

a

40m/s

b

20m/s

c

30m/s

d

10 m/s

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Area under acceleration - time graph = change in velocity

12(4+2)×10=v0

V=30ms-1

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon