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Q.

A particle starts from rest with acceleration 2m/s2 .The acceleration of the particle decreases down to zero uniformly during time-interval of 4s. The velocity of particle after 2s is

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a

zero

b

8 m/s

c

3 m/s

d

4 m/s

answer is A.

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Detailed Solution

Acceleration decreases at the rate of
2−04=0.5m/s2

∴ acceleration after 2 sec = 2 – 0.5 × 2 = 1m/s2

∴ Average acceleration in 2sec is 2 + 1/2 = 3/2

V = u + at = 0 + 3/2 x 2 = 3m/s

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