Courses
Q.
A particle starts from rest with acceleration The acceleration of the particle decreases down to zero uniformly during the time interval of 4 s. The velocity of the particle after 2 s is
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
a
zero
b
8 m/s
c
3 m/s
d
4 m/s
answer is A.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
In this problem, we are given that a particle starts moving with acceleration 2m/s² and that the acceleration decreases uniformly to zero over a period of 4 seconds. We are required to find the velocity of the particle after 2 seconds.
Step 1: Understanding the Variation of Acceleration
Since a particle starts moving with acceleration 2m/s² and the acceleration decreases uniformly to zero, we can describe the variation of acceleration as a linear function of time. This means that the acceleration is given by the equation:
a = mt + c
Where m
is the slope of the acceleration-time graph, and c
is the initial acceleration. Now, we can use the information provided in the problem to find the values of m
and c
.
Step 2: Finding the Value of c
At time t = 0
, we know that the acceleration is 2 m/s². Therefore, by substituting these values into the equation for acceleration:
2 = m × 0 + c
From this equation, we get that c = 2.
Step 3: Finding the Value of m
Next, we are told that after 4 seconds, the acceleration has decreased to zero. At t = 4s, the acceleration is 0 m/s². Using this information, we substitute into the acceleration equation:
0 = m × 4 + 2
Solving for m, we get:
m = -1/2
Step 4: Equation for Acceleration
Now that we have both values for m and c, we can substitute them back into the original equation for acceleration:
a = -t/2 + 2
Step 5: Finding the Velocity after 2 Seconds
We know that velocity is the integral of acceleration with respect to time. Therefore, to find the velocity of the particle after 2 seconds, we can integrate the acceleration equation with respect to time:
∫(0 to v) dv = ∫(0 to 2) (-t/2 + 2) dt
Now, performing the integration:
v = 3 m/s
Final Answer
Thus, the velocity of the particle after 2 seconds is 3 m/s.
In conclusion, when a particle starts moving with acceleration 2m/s², and the acceleration decreases uniformly to zero in 4 seconds, the velocity of the particle after 2 seconds is 3 m/s.