A particle starts from the origin at t = 0 sec with a velocity of 10.0 j^ m/s and moves in plane with a constant acceleration of (8i^+2j^) m/s2. The y-coordinate of the particle in 2 sec is

Sy=Uyt+12ayt2=(10)(2)+12(2)(2)2=24 m

Sy=Uyt+12ayt2=(10)(2)+12(2)(2)2=24 m

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A particle starts from the origin at t = 0 sec with a velocity of $10 .0 \hat{j} m / s$ and moves in plane with a constant acceleration of $(8 \hat{i} + 2 \hat{j}) m / s^{2}$ . The y-coordinate of the particle in 2 sec is

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16 m

24 m

8 m

12 m

answer is C.

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$S_{y} = U_{y} t + \frac{1}{2} a_{y} t^{2}$

$= (10) (2) + \frac{1}{2} (2) (2)^{2}$

$= 24 m$

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