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A particle starts from the origin, goes along X-axis to the point (20 m, 0) and then returns along the same line to the point (-20 m, 0).The distance and displacement of the particle during the trip are:

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40 m, 0

40 m, 20 m

40 m, -20m

60 m, -20 m

answer is D.

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Detailed Solution

Distance = Total movement of particle = $|20| + |20| + |20| = 60 m$

Displacement = Net movement of particle = Final position - Initial position = -20 - 0 = -20 m

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