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Q.

A particle starts its motion from rest under the action of a constant force. If the distance covered in first 10 seconds is $S_{1}$ and that covered in first 20 seconds is $S_{2}$ , then:

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a

$S_{2} = 3 S_{1}$

b

$S_{2} = 2 S_{1}$

c

$S_{2} = S_{1}$

d

$S_{2} = 4 S_{1}$

answer is C.

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Detailed Solution

$S_{1} = \frac{1}{2} a {(10)}^{2}$

$S_{2} = \frac{1}{2} a {(20)}^{2}$

From the above equations we get $S_{2} = 4 S_{1}$

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