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Q.

A particle starts moving with initial velocity of 3 m/s along x-axis from origin. Its acceleration  is varying with position  (x) in parabolic nature with vertex at the origin as shown in figure. A tangent to the graph is drawn at  x=3m. The tangent makes an angle of  600 with the x-axis. At this position the velocity of particle is 3+k m/s  the value of  k is

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answer is 9.

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Detailed Solution

 a=kx2
dadx=2kx
At  x=3dadx=3k=12
vdvdx=12x2  vdv=x2dx2
v2u22=12(x33)03
v2=9+3v=9+3

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