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A particle starts oscillating along a line segment AB of length 40 m. If it takes 5 s for each oscillation, its average speed and magnitude of average velocity at the end of 10 oscillation

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16 {ms}^{- 1}, 32 {ms}^{- 1}

8 {ms}^{- 1}, 0

0, 16 {ms}^{- 1}

16 {ms}^{- 1}, 0

answer is D.

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Detailed Solution

Let the distance covered per each oscillation = 80m (to & fro)

Number of oscillations = 10

Time period = 5s

We can have

$v_{Avg} = \frac{total distance}{Total time}$

Total distance = 800m

Total time $= 5 \times 10 s = 50 s$

$v_{Avg} = \frac{800}{5} = \frac{80}{5} = 16 m/s$

$\bar{v} = 0$

$v = 16 m/s, 0$

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