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Q.

A particle starts oscillating along a line segment AB of length 40 m. If it takes 5 s for each oscillation, its average speed and magnitude of average velocity at the end of 10 oscillation                                                     

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a

16ms1,0

b

16ms1,32ms1

c

8ms1,0

d

0,16ms1

answer is D.

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Detailed Solution

Let the distance covered per each oscillation = 80m (to & fro)

Number of oscillations = 10

Time period = 5s

We can have

vAvg=totaldistanceTotaltime

Total distance = 800m

Total time=5×10s=50s

vAvg=8005=805=16m/s

v¯=0

v=16m/s,0

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