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Q.

A particle starts SHM from the mean position. Its amplitude is A and its time period is T. At one time its speed is half that of the maximum speed. Its displacement is

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a

$\frac{3 A}{\sqrt{2}}$

b

$\frac{\sqrt{2} A}{3}$

c

$\frac{2 A}{3}$

d

$\frac{\sqrt{3} A}{2}$

answer is B.

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Detailed Solution

detailed_solution_thumbnail

$V = ω \sqrt{A^{2} - x^{2}} \Rightarrow \frac{A ω}{2}$

$= ω \sqrt{A^{2} - x^{2}} = \frac{\sqrt{3}}{2} A .$

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