Q.

A particle which is constrained to move along x-axis, is subjected to a force in the same direction which varies with the distance x of the particle from the origin as F(x)=kx+ax3. Here k and a are positive constant .for x0, the functional form of potential energy U (x) of the particle is

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a

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b

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c

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d

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answer is D.

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Detailed Solution

F=dUdx, U=kx22ax44  At very small values, x4<<x2 and U will be positive.   and U=0 when k2=ax24. After this U will be negative. 

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