A particle with charge ‘-q’ and mass ‘m’ enters a magnetic field of magnitude ‘B’ existing only to the right of the boundary YZ. The direction of motion of the particle is perpendicular to the direction of ‘B’. Let $T = \frac{2 π m}{q B}$ . The time spent by the particle in the field will be

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$(\frac{π - θ}{π}) T$

$(\frac{π + 2 θ}{π}) T$

$(\frac{π - 2 θ}{π}) T$

$(\frac{θ}{π}) T$

answer is D.

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Detailed Solution

Force acting on the charged particle according to Fleming's left hand rule is outside the magnetic field region and towards the center of the circle. According to the diagram time taken to travel an angle 2 $θ$ is $t= (\frac{2 θ}{2 π}) T$

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