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Q.

A particular reaction has a rate constant 1.15×103s1 how long does it take for 6gm of the reactant to reduce to 3gm ( in sec)

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a

301

b

603

c

840

d

15

answer is B.

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Detailed Solution

k=2.303tlog(A0A)

1.15×103=2.303tlog(63)

t=2.3031.15×103×log2

=602.78603sec

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