A passenger train of length 60 m travels at a speed of 80 km/h. Another freight train of length 120 m travels at a speed of 30 km/h. The ratio of times taken by the passenger train to completely cross the freight train when: (i) they are moving in the same direction and (ii) in the opposite direction is

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$\frac{25}{11}$

$\frac{3}{2}$

$\frac{11}{5}$

$\frac{5}{2}$

answer is C.

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Detailed Solution

In the first case $V_{1} - V_{2} = \frac{l_{1} + l_{2}}{t_{1}} \Rightarrow t_{1} = \frac{l_{1} + l_{2}}{V_{1} - V_{2}}$

And in second case $V_{1} + V_{2} = \frac{l_{1} + l_{2}}{t_{1}} \Rightarrow t_{1} = \frac{l_{1} + l_{2}}{V_{1} + V_{2}}$

From the above we get $\frac{t_{1}}{t_{2}} = \frac{11}{5}$

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