AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A path separates two walls. A ladder leaning against one wall rests at a point on the path. It reaches a height of 90 m on the wall and makes an angle of $60 °$ with the ground. If while resting at the same point on the path, it were made to lean against the other wall, it would have made an angle of $45 °$ with the ground. Find the height it would have reached on the second wall.

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

406 m

106 m

206 m

306 m

answer is C.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Given that the ladder reaches a height of 90 m and makes an angle of

60 °

with the ground.
We have to find the height reached by the same on the second wall.
Suppose,

A B = 90 m

be the height of the wall and

X = A E = D E

be the be the length of the ladder. Assume the height it would have when it reached the second wall be DC. Then, by using the figure geometry,
Question Image

In triangle ABE,

sin θ = A B A E ⇒ sin 60 ° = 90 x ⇒ 32 = 90 x ∴ x = 1803

In triangle DCE,

sin θ = D C D E ⇒ sin 45 ° = D C x ⇒ 12 = D C 1803 ⇒ D C = 306 m

The height is

306 m

.
Therefore, the correct option is 3.

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!