A pendulum bob has a speed 3 m/s while passing through its lowest position, length of the pendulum is 0.5 m then its speed when it makes an angle of 60° with the vertical is $(g = 10 m / s^{2})$

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2 m/s

3 m/s

1 m/s

4 m/s

answer is A.

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Detailed Solution

$h = l - lcos 60 = l - l \times \frac{1}{2} = l / 2$
by law of conservation of mechanical energy $\frac{1}{2} {mu}^{2} = \frac{1}{2} {mv}^{2} + mgh$
$∴ v^{2} = u^{2} - 2 g \frac{l}{2}$
$v = \sqrt{{(3)}^{2} - 10 \times \frac{1}{2}} = 2 m / s$

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