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Q.

A pendulum bob has a speed of 3ms−1  at its lowest position. The pendulum is 0.5 m long. Find the speed of the bob in  ms−1, when the length makes an angle of  60∘  to the vertical.  [g=10ms−2] 

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answer is 2.

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Detailed Solution

12mυ12+mgl(1−cosθ)=12mυ2 ⇒υ12+2gl(1−cosθ)=υ2 ⇒υ12+2×10×0.5(1−12)=9⇒υ12=9−5=4⇒υ1=2 ms−1

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