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Q.

A pendulum bob has a speed of 3 ms-1 at its lowest position. The pendulum is 0.5 m long. The speed of the bob, when the length makes an angle of 600 to the vertical, will be:

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a

ms-1

b

ms-1

c

13 ms-1

d

12 ms-1

answer is D.

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Detailed Solution

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12mv2+mgl(1-cos θ) = 12mv'2

or      v2+2gl(1-cosθ) = v2

or      v2+2×10×0.5(1-12) = 9

or  v2 = 9-5 = 4

or v = 2 ms-1

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