A pendulum bob of mass 1 kg is released from rest when the string (of length 1m) is just taut and horizontal List-I List-II P) Tension (in N) in the string at θ=300 1) 10Q) Velocity (in m/s) of the bob at θ=300 2) 15 R) Total acceleration (in m/s2) of the bob at θ=300 3) 20 S) Total acceleration (in m/s2) when θ=900 4) 57

V=2glsinθT=mgsinθ+mv2la=(gcosθ)2+(V2l)2

A pendulum bob of mass 1 kg is released from rest when the string (of length 1m) is just taut and horizontal List-I List-II P) Tension (in N) in the string at θ=300 1) 10Q) Velocity (in m/s) of the bob at θ=300 2) 15 R) Total acceleration (in m/s2) of the bob at θ=300 3) 20 S) Total acceleration (in m/s2) when θ=900 4) 57

V=2glsinθT=mgsinθ+mv2la=(gcosθ)2+(V2l)2

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A pendulum bob of mass 1 kg is released from rest when the string (of length 1m) is just taut and horizontal

List-I List-II
P) Tension (in N) in the string at $θ = 30^{0}$ 1) $\sqrt{10}$
Q) Velocity (in m/s) of the bob at    $θ = 30^{0}$      2) 15
R) Total acceleration (in m/s²) of the bob at $θ = 30^{0}$       3) 20
S) Total acceleration (in m/s²) when $θ = 90^{0}$         4) $5 \sqrt{7}$

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P-2; Q-1; R-4; S-3;

P-1; Q-2; R-4; S-3;

P-4; Q-1; R-2; S-3;

P-2; Q-4; R-1; S-3;

answer is A.

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Detailed Solution

$\begin{array}{l} V = \sqrt{2 g l \sin θ} \\ T = m g \sin θ + \frac{m v^{2}}{l} \\ a = \sqrt{{(g \cos θ)}^{2} + {(\frac{V^{2}}{l})}^{2}} \end{array}$

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