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A pendulum bob of mass $30 .7 \times 10^{- 6} kg$ and carrying a charge $2 \times 10^{- 8} C$ is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is $(g = 9 .8 m / s^{2})$

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$3 \times 10^{- 4} N$

$4 \times 10^{- 4} N$

$5 \times 10^{- 4} N$

$6 \times 10^{- 4} N$

answer is C.

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Detailed Solution

$\begin{array}{l} T = \sqrt{(mg)^{2} + (QE)^{2}} \\ = \sqrt{{(30 .7 \times 10^{- 6} \times 9 .8)}^{2} + {(2 \times 10^{- 8} \times 20000)}^{2}} = 5 \times 10^{- 4} N \end{array}$

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