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A perfect gas at 27 $° c$ is heated at constant pressure so as to double its volume. The temperature of the gas will be

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300 $°$ C

200 $°$ C

327 $°$ C

600 $°$ C

answer is C.

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Detailed Solution

$\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}} \Rightarrow \frac{V}{300} = \frac{2 V}{T} T = 600 k = 600 - 273 = 327 ° C$

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