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A perfect gas goes from state A to state B by absorbing 8 X $10^{5}$ J of heat and doing 6.5 x 10⁵ J of external work. It is now transferred between the same two states in another process in which it absorbs 10⁵ J of heat. In the second process

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work done on the gas is 10⁵ J

work done on the gas is 0.5 X 10⁵J

work done by the gas is 10⁵ J

work done by the gas is 0.5 X 10⁵ J

answer is B.

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Detailed Solution

According to first law of thermodynamics,

$d U = d Q - d W$

$d U = 8 \times 10^{5} - 6.5 \times 10^{5} = 1.5 \times 10^{5} J$

In the second process, dU remains the same.

$∴ d W = d Q - d U = 1 \times 10^{5} - 1.5 \times 10^{5}$

$d W = - 0.5 \times 10^{5} J$

$∴$ Work done on the gas is $0.5 \times 10^{5} J$

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