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A person brings a mass of 1 kg from infinity to a point A. Initially the mass was at rest but it moves at a speed of $2 m / s$ as it reaches A. The work done by the person on the mass is –3J. The potential at A is

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–1 J/kg

–3 J/kg

–5 J/kg

–2 J/kg

answer is C.

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Detailed Solution

$\begin{array}{l} W = ΔU + K \cdot E \Rightarrow - 3 = (U_{A} - 0) + \frac{1}{2} \times 1 \times (4) \\ U_{A} = - 3 - 2 = - 5 J \\ V_{A} = \frac{∆ U}{m} = - 5 J / kg \end{array}$

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