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A person brings a mass of $1 k g$ from infinity to a point $A$ . Initially, the mass was at rest but it moves at a speed of $3 m / s$ as it reaches $A$ . The work done by the person on the mass is $- 5.5 J$ . The gravitational potential at $A$ is

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$- 1 J / k g$

$- 4.5 J / k g$

$- 5.5 J / k g$

$- 10 J / k g$

answer is D.

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Detailed Solution

$W = Δ E = E_{A} - E_{α}$

$= (K_{A} + U_{A}) - (K_{α} + U_{α})$

$= (K_{A} + m V_{A}) - (0 + 0)$

$∴ - 5.5 = \frac{1}{2} \times 1 \times (3)^{2} + (1) V_{A}$

or $V_{A} = - 10 J / k g$

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