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A person can throw a ball upto a maximum range of 100 m. How high above the ground he can throw the same ball?

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25 m

200 m

100 m

50 m

answer is B.

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Detailed Solution

$\begin{array}{l} R = \frac{u^{2} \sin 2 θ}{g} \Rightarrow R_{max} = \frac{u^{2}}{g} = 100 m; \\ again, H_{max} = \frac{u^{2}}{2 g} = \frac{100}{2} = 50 m \end{array}$

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