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A person goes 10 km north and 20 km east. What will be displacement from initial point?

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22.36 km

2 km

5 km

20 km

answer is A.

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Detailed Solution

$\vec{AC} = \vec{AB} + \vec{BC}$

AC = $\sqrt{{(AB)}^{2} + {(BC)}^{2}}$

= $\sqrt{{(10)}^{2} + {(20)}^{2}}$

= $\sqrt{100 + 400} = \sqrt{500}$

= 22.36 km

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