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A person holds a block weighing 2kg between his hands & keeps it from falling down by pressing it with his hands. If the force exerted by each hand horizontally is 50N, the co-efficient of friction between the hand & the block is $(g = 10 {ms}^{- 2})$

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0.2

0.4

0.1

0.5

answer is A.

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Detailed Solution

2 f = mg

$μ (2 \times 50) = 2 \times 10$

$μ (100) = 20$

$μ = \frac{20}{100}$

$μ = \frac{1}{5}$

$μ = 0.2$

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