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Q.

A person in lift which ascents up with acceleration 10 ms-2 drops a stone from a height 10m. The time of decent is [g=10ms-2]

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a

3 s

b

1 s

c

1.5 s

d

2 s

answer is A.

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Detailed Solution

Relative acceleration of the stone in the lift is g+a. 

time of descent of the stone is 

T=2h(g+a)=2×1010+10T=1s

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