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A person Invites 8 guests to a dinner and places 5 of them at one table and the remaining 3 at another, both the tables being round. The number of ways in which the guests can be arranged is

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40320

2688

8064

13340

answer is B.

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Detailed Solution

No of ways in which 8 guests can be divided into 2 groups containing 5, 3 is $8 C_{3} = \frac{8!}{3! 5!} = 56$

5 guests can be arranged Around a table = 4!

3 guests can be arranged Around a table = 2!

No of circular permutations = 56 (4!) (2!)

= 2688

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