A person Invites 8 guests to a dinner and places 5 of them at one table and the remaining 3 at another, both the tables being round. The number of ways in which the guests can be arranged is

No of ways in which 8 guests can be divided into 2 groups containing 5, 3 is $8{\mathrm{C}}_3=\frac{8!}{3!5!}=56$

5 guests can be arranged Around a table = 4!

3 guests can be arranged Around a table = 2!

No of circular permutations = 56 (4!) (2!)

                                                      = 2688