A person is standing at a distance 's' m from a bus. The bus begins to move with constant acceleration 'a' m/s2 away from the person. To catch the bus, the person runs at a constant speed 'v' m/s towards the bus. Minimum speed of the person so that he can catch the bus is:

By using v2 = u2 + 2as for relative motion of man w.r.t. bus02=vmin2-2as⇒vmin=v=2as

A person is standing at a distance 's' m from a bus. The bus begins to move with constant acceleration 'a' m/s2 away from the person. To catch the bus, the person runs at a constant speed 'v' m/s towards the bus. Minimum speed of the person so that he can catch the bus is:

By using v2 = u2 + 2as for relative motion of man w.r.t. bus02=vmin2-2as⇒vmin=v=2as

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A person is standing at a distance 's' m from a bus. The bus begins to move with constant acceleration 'a' m/s² away from the person. To catch the bus, the person runs at a constant speed 'v' m/s towards the bus. Minimum speed of the person so that he can catch the bus is:

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$\sqrt{2 as}$

$\sqrt{as}$

$\sqrt{3 as}$

$\sqrt{\frac{as}{3}}$

answer is A.

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By using v² = u² + 2as for relative motion of man w.r.t. bus
$0^{2} = v_{\min}^{2} - 2 as \Rightarrow v_{\min} = v = \sqrt{2 as}$

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A person is standing at a distance 's' m from a bus. The bus begins to move with constant acceleration 'a' m/s2 away from the person. To catch the bus, the person runs at a constant speed 'v' m/s towards the bus. Minimum speed of the person so that he can catch the bus is:

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A person is standing at a distance 's' m from a bus. The bus begins to move with constant acceleration 'a' m/s² away from the person. To catch the bus, the person runs at a constant speed 'v' m/s towards the bus. Minimum speed of the person so that he can catch the bus is: