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A person is standing on a platform rotating with an angular speed $ω$ ,with stretched hands carrying equal masses each of m. Now he releases the masses such that they fall on the platform. The new angular velocity of platform would be

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$2 ω /3$

$2 ω$

$ω$

$ω /2$

answer is A.

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Detailed Solution

There will be no change in the angular speed of the platform though masses are released on to the platform

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