A person is standing on a truck moving with a constant velocity of $14.7 m / s$ on a horizontal road. The man throws a ball in such a way that it returns to the truck after the truck has moved $58.8 m$ .

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

Angle of projection is $53 °$ with horizontal seen from ground

Speed of ball is $19.6 m / s$ upward as seen from truck

Speed of ball is $19.6 m / s$ upward as seen from road

Angle of projection is $30 °$ with horizontal seen from truck

answer is A, D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Angle of projection as seen from the truck $= 90 °$
Time taken by truck : $t = \frac{s}{v t} = \frac{58.8}{14.7} = 4 s$
$u = \frac{t g}{2 \sin θ} = \frac{4 \times 9.8}{2 \times 1} = 19.6 m / s$
As seen from the road $v = \sqrt{u_{x}^{2} + u_{y}^{2}} = \sqrt{v_{t}^{2} + u^{2}}$
$θ = \tan^{- 1} (\frac{19.6}{14.7}) = \tan^{- 1} (1.33) = 53 °$