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Q.

A person moved from A to B on a circular path as shown is fig.

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If the distance travelled by him is 90m, then the magnitude of displacement would be (Given cos1350=−0.7)

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a

19.37 m

b

42.26 m

c

70.46 m

d

40.87 m

answer is B.

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Detailed Solution

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d=Rθ

90 =R(3π4)

R=90×43π=120π

∴Displacement =R2+R2−2R2cos1350=3.4R2=3.4(120π)2≈70.46m

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