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Q.

A person of 60 Kg mass is in a lift which is coming down such that the man exerts a force of 150 N on the floor of the lift. Then the acceleration of the lift is (g=10ms–2)

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a

40.0 ms-2

b

15.0 ms-2

c

22.5 ms-2

d

7.5 ms-2

answer is D.

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Detailed Solution

According to the second law of motion

Fnet=ma⇒mg-N=ma

⇒N=m(g-a)⇒150=60(10-a)⇒a=7.5ms-2

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