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A person of mass 60 kg stands on a weighing machine in a lift which is moving
(a) upwards with a uniform retardation of $2.8 m s^{- 2}$

(b) downwards with a uniform retardation of $2.2 m s^{- 2}$ . Find the reading shown by the weighing machine in each case.

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720 N ; 420 N

320 N ; 520 N

640 N ; 720 N

420 N; 720 N

answer is A.

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Detailed Solution

$R = m (g - a) = 60 (9.8 - 2.8)$

$= 60 \times 7 = 420 N$

$R = m (g + a) = 60 (9.8 + 2.2)$

$= 60 \times 12 = 720 N$

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