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A person of mass 60 kg is in a lift. The change in the apparent weight of the person, when the lift moves up with an acceleration of 2ms^-2 and then down with an acceleration of 2ms^-2 , is (take g = 10 m/sec²)

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answer is B.

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Detailed Solution

w₁ = m(g + a),w₂ = m(g - a)

$w_{1} - w_{2} = 2 m a$

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