A person sitting in the ground floor of a building notices through the window, of height 1.5 m, a ball dropped from the roof of the building crosses the window in 0.1 s. What is the velocity of the ball when it is at the topmost point of the window ? ( $g = 10 m / s^{2}$ )

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14.5 m/s

20 m/s

4.5 m/s

15.5 m/s

answer is C.

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Detailed Solution

From equation of motion

$\begin{array}{l} S = ut + \frac{1}{2} {at}^{2} \\ 1.5 = u (0.1) + \frac{1}{2} \times 10 (0.1)^{2} \\ 1.5 = (0.1) u + 0.05 \\ u = 15 - 0.5 \\ = 14.5 m / s \end{array}$

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