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Q.

A person standing between two parallel hills fires a gun. He hears the first echo after 1.5 sec and second echo after 2.5 sec. If speed of sound is 332ms-1, the distance between the hills is

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a

664m

b

654m

c

644m

d

634m

answer is A.

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Detailed Solution

Question Image

First echo = 1.5 s
Speed of sound = 332  
2d1=1.5×332d1=1.5×3322=249m
Second echo = 2.5 s
Speed of sound = 332ms-1  
2d2=2.5×332=830d2=8302=415md=d1+d2d=664m

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