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Q.

A person standing on a spring balance inside a stationary lift measures 60kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8 m/ s2 will be __________N. [ g = 10 m / s2 ]

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answer is 492.

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Detailed Solution

Mass of the person, M = 60kg
Tension in the rope of the lift when it moves downward with acceleration a,
T = M(g-a) = 60(10-1.8) = 492 N.

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