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Q.

A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of  1.8  m/s2 will be _______ N. [g=10 m/s2]

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answer is 492.

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Detailed Solution

Question Image

When lift is at rest
  N=mg       
⇒    60×10=600N 
When lift moves with downward acceleration.
 Question Image
In frame of lift pseudo force will be in upward direction.
N'=M(g−a)       ⇒    60(10−1.8) N'    ⇒    492 N

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