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A person standing on the floor of an elevator drops a coin. The coin reaches the floor in time $t_{1}$ if the elevator is at rest and in time $t_{2}$ if the elevator is moving uniformly. Then :

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$t_{1} > t_{2} o r t_{1} < t_{2}$ depending upon whether the lift is going up or down

$t_{1} < t_{2}$

$t_{1} > t_{2}$

$t_{1} = t_{2}$

answer is D.

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Detailed Solution

In both case elevator is an inertial frame of reference so effective gravity remains same from both the frames. So, time of fall remains same in both cases (since initial velocity is same in both frames). Hence $t_{1} = t_{2}$

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