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Q.

A person suffering from defective vision can see objects clearly only beyond 100 cm from the eye. Find the power of lens required so that he can see clearly the object placed at a distance of distinct vision (D = 25cm)

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a

2D

b

–3D

c

–2D

d

3D

answer is B.

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Detailed Solution

Person has long sight ; $v = - 100 cm, u = - 25 cm$
$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}; f = \frac{100}{3} cm$

$P = \frac{100}{f} = \frac{\frac{100}{100}}{3} = 3 D$

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