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A person walking at the rate of 3km/hr, the rain appears to fall vertically when he increase his to speed 6 km/hr it appears to meet him at angle of $45^{0}$ with vertical. The speed of rain is

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$\frac{3}{\sqrt{2}} k m / h r$

$2 \sqrt{3} k m / h r$

$6 \sqrt{2} k m / h r$

$3 \sqrt{2} k m / h r$

answer is A.

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Detailed Solution

${\vec{v}}_{r}$ should be same in both the situations.
Thus, $| {\vec{v}}_{r} | 3 \sqrt{2} k m / h r$

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