A person walks up a stalled escalator in 90 s. When just standing on the same moving escalator, he is carried in 60s. The time it would take him to walk up the moving escalator will be

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27 s

50 s

18 s

36 s

answer is D.

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Detailed Solution

$v_{1} = \frac{s}{90}, v_{2} = \frac{s}{60} N o w, t = \frac{s}{v_{1} + v_{2}} = \frac{s}{\frac{s}{90} + \frac{s}{60}} = \frac{90 \times 60}{90 + 60} = 36 s$

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