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Q.

A person wears glases of power –2.5 D. The defect of the eye and far point of the person without glasses are respectively

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a

far sightedness, 40 cm

b

near sightedness, 40 cm

c

near sightedness, 250 cm

d

astigmatism, 40 cm

answer is B.

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Detailed Solution

P=-100 farpoint 

-2.5=-100 far point 

far point = 40cm, the type of defect is near sightedness.

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A person wears glases of power –2.5 D. The defect of the eye and far point of the person without glasses are respectively