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A person with a myopic eye cannot see objects beyond 1.2 m distinctly. Then the nature of corrective lens to restore proper vision should be

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$- 0 .83 D$

0.83 D

$- 2.83 D$

2.83 D

answer is A.

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Detailed Solution

$u = - \propto v = - 120 cm \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \Rightarrow \frac{1}{f} = - \frac{1}{120} + \frac{1}{\infty} \Rightarrow f = - 120 cm \cdot P = \frac{- 100}{120} = - 0 .83 D$

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